2g^2+7g=6=0

Solution for 2g^2+7g=6=0 equation:

2g^2+7g=6=0

We move all terms to the left:

2g^2+7g-(6)=0

a = 2; b = 7; c = -6;
Δ = b2-4ac
Δ = 72-4·2·(-6)
Δ = 97
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{97}}{2*2}=\frac{-7-\sqrt{97}}{4}
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{97}}{2*2}=\frac{-7+\sqrt{97}}{4}
$